2[t-(4t+18)+16]=2(t+2)

Solution for 2[t-(4t+18)+16]=2(t+2) equation:

Simplifying
2[t + -1(4t + 18) + 16] = 2(t + 2)

Reorder the terms:
2[t + -1(18 + 4t) + 16] = 2(t + 2)
2[t + (18 * -1 + 4t * -1) + 16] = 2(t + 2)
2[t + (-18 + -4t) + 16] = 2(t + 2)

Reorder the terms:
2[-18 + 16 + t + -4t] = 2(t + 2)

Combine like terms: -18 + 16 = -2
2[-2 + t + -4t] = 2(t + 2)

Combine like terms: t + -4t = -3t
2[-2 + -3t] = 2(t + 2)
[-2 * 2 + -3t * 2] = 2(t + 2)
[-4 + -6t] = 2(t + 2)

Reorder the terms:
-4 + -6t = 2(2 + t)
-4 + -6t = (2 * 2 + t * 2)
-4 + -6t = (4 + 2t)

Solving
-4 + -6t = 4 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
-4 + -6t + -2t = 4 + 2t + -2t

Combine like terms: -6t + -2t = -8t
-4 + -8t = 4 + 2t + -2t

Combine like terms: 2t + -2t = 0
-4 + -8t = 4 + 0
-4 + -8t = 4

Add '4' to each side of the equation.
-4 + 4 + -8t = 4 + 4

Combine like terms: -4 + 4 = 0
0 + -8t = 4 + 4
-8t = 4 + 4

Combine like terms: 4 + 4 = 8
-8t = 8

Divide each side by '-8'.
t = -1

Simplifying
t = -1